If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2-4=2x^2-68
We move all terms to the left:
3x^2-4-(2x^2-68)=0
We get rid of parentheses
3x^2-2x^2+68-4=0
We add all the numbers together, and all the variables
x^2+64=0
a = 1; b = 0; c = +64;
Δ = b2-4ac
Δ = 02-4·1·64
Δ = -256
Delta is less than zero, so there is no solution for the equation
| 2(3x-4=8x-10 | | 3x+19=106 | | 5c+35=65 | | 8y=74 | | 21-2x^2=9 | | 2x2+16x-96=0 | | 1/4(12x+27)=-15 | | 5x-(8+x)=4+3-(x+7) | | 3(2+x)=17 | | 10x+20=5x-40 | | 6(2x-6)=9(x+6) | | 3x=14=3x+24 | | 21n=49n= | | 5x+2=12x+8 | | 3=2x^2-3 | | 5y-10=3y+50 | | 4(x-7/2)^2-1=0 | | 5+2x=-25x | | p2-7p+12=0. | | 2x+10=12x-30 | | 5x(2x-1)+3(2x-1)=0 | | 1/2v=7/8 | | 4/3k=12 | | 4/3k=12/1 | | 22/9y=10/1 | | 120=1.5z | | 31/3x=13/5 | | 1/4(x+3)^2-1=0 | | 7/4p=14 | | -14=19-x | | 5m=10/3 | | 1+-1=n |